A trapezium ABCD, in which AB is parallel to CD, is inscribed in a circle with centre O. Suppose the diagonals AC and BD of the trapezium intersect at M, and OM $=$ 2. If $\angle$AMB is 60$^{\circ}$, the difference between the lengths of the parallel sides is X$\sqrt{3}$. Find the value of X.

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