Multiple choice

A die is thrown 6 times. If getting an odd number' is a success, then the probability 5 successes is :

  1. $\frac{3}{32}$
  2. $\frac{23}{5}$
  3. $\frac{32}{5}$
  4. $\frac{15}{32}$
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A Correct answer
Explanation

Using binomial probability P(X=k) = C(n,k) * p^k * q^(n-k). n=6, k=5, p=1/2, q=1/2. P(X=5) = C(6,5) * (1/2)^5 * (1/2)^1 = 6 * (1/2)^6 = 6/64 = 3/32.

AI explanation

The probability of getting an odd number on a single die is 1/2. Using the binomial probability formula, the probability of 5 successes in 6 throws is given by 6C5 multiplied by (1/2)^5 and by (1/2)^1. This evaluates to 6 multiplied by 1/64, which equals 6/64 or 3/32. The probability is 3/32.