Multiple choice

Two uniform dice marked $1$ to $6$ are thrown together The probability that the sum is neither $7$ nor $11$ is

  1. $\dfrac{2}{9}$
  2. $\dfrac{5}{9}$
  3. $\dfrac{7}{9}$
  4. $\dfrac{4}{9}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total outcomes = 36. Sum of 7 occurs in 6 ways (1,6; 2,5; 3,4; 4,3; 5,2; 6,1). Sum of 11 occurs in 2 ways (5,6; 6,5). Total ways for 7 or 11 = 8. Probability = 8/36 = 2/9. Probability of neither = 1 - 2/9 = 7/9.

AI explanation

When two dice are thrown, the total number of outcomes is 36. The sum of 7 occurs in 6 ways and the sum of 11 occurs in 2 ways, making 8 total favorable outcomes for the event. The probability of the sum being neither 7 nor 11 is (36 - 8) / 36 = 28/36, which simplifies to 7/9.

Keep practicing — related questions