Multiple choice

A bag contains 4 white and 5 black balls. A second bag contains 3 (identical) white and 6 (identical) black balls. One bag is chosen at random and a ball is drawn. Its colour is noted and the ball replaced. This is repeated four times. It was found that of these four, one was white and 3 were black. The $n$ the probability that the first bag was chosen is

  1. $\dfrac{162}{287}$
  2. $\dfrac{125}{287}$
  3. $\dfrac{250}{280}$
  4. $\dfrac{125}{574}$
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B Correct answer