AB, BC and CD are three consecutive sides of a regular polygon. If $\angle BAC = $$20^{\circ}$, Find the number of sides in the polygon

In a regular polygon, the angle subtended by a side at the center is 360/n. The angle between two consecutive sides is (n-2)*180/n. The triangle formed by the center and two vertices is isosceles. The angle BAC is 20 degrees. For a regular polygon, the angle subtended by a side at the circumference is 180/n. Here, the angle BAC involves 2 sides, so 2 * (180/n) = 20? No, that's not right. The angle subtended by a side at any point on the circumference is 180/n. If BAC = 20, then 180/n = 20, so n = 9.