Multiple choice

A car moving with velocity which is measured each second and the data is recorded as per the table below. Velocity Time $0$ $0$ $2 {m}/{s}$ $1 s$ $4 {m}/{s}$ $2 s$ $6 {m}/{s}$ $3 s$ $8 {m}/{s}$ $4 s$ If the object stops accelerating at $4 s$ when its speed is $8 {m}/{s}$, Find out the distance it will travel between $4 s$ and $7 s$ .

  1. $8 m$
  2. $16 m$
  3. $18 m$
  4. $24 m$
  5. $32 m$
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D Correct answer
Explanation

After 4 seconds, the object stops accelerating, so its speed remains constant at 8 m/s. Over the next 3 seconds, the distance travelled is 8 × 3 = 24 m.

AI explanation

Since the object stops accelerating at 4 seconds, it travels at a constant velocity of 8 m/s from 4 seconds to 7 seconds. The time interval is 7 seconds minus 4 seconds, which equals 3 seconds. Using the distance formula for uniform motion, distance equals speed multiplied by time, so 8 m/s multiplied by 3 seconds gives a distance of 24 m.

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