Multiple choice

If two dice are thrown, what is the probability that at least one of the dice shows a number greater than 3?

  1. $\displaystyle \frac{3}{4}$
  2. $\displaystyle \frac{1}{4}$
  3. $\displaystyle 1$
  4. $\displaystyle \frac{1}{3}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Probability of getting a number <= 3 on one die is 3/6 = 1/2. Probability of getting <= 3 on both dice is 1/2 * 1/2 = 1/4. Probability of at least one > 3 is 1 - 1/4 = 3/4.

AI explanation

Using the complementary event approach, we first find the probability that both dice show numbers less than or equal to 3. The numbers less than or equal to 3 are 1, 2, and 3, giving 3 options for each die and 9 total outcomes for both dice. The probability of this complementary event is 9 divided by 36, which is 1/4. We subtract this from 1 to find the probability that at least one die shows a number greater than 3, yielding 1 - 1/4 = 3/4.

Keep practicing — related questions