Multiple choice

The probability that in the toss of two dice we obtain the sum 7 or 11 is

  1. $\displaystyle \frac{1}{6}$
  2. $\displaystyle \frac{1}{18}$
  3. $\displaystyle \frac{2}{9}$
  4. $\displaystyle \frac{23}{108}$
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C Correct answer
Explanation

Total outcomes = 36. Sum 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) -> 6 outcomes. Sum 11: (5,6), (6,5) -> 2 outcomes. Total favorable = 8. Probability = 8/36 = 2/9.

AI explanation

When two dice are thrown, there are 36 possible outcomes. A sum of 7 occurs in 6 ways (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1), while a sum of 11 occurs in 2 ways (5,6) and (6,5). The total number of favorable outcomes is 6 + 2 = 8. We divide 8 by 36 to get the probability, which simplifies to 2/9.

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