Multiple choice

Two uniform dice marked $1$ to $6$ are thrown together. The probability that the score on the two dice is at least seven is

  1. $\dfrac{5}{12}$
  2. $\dfrac{7}{12}$
  3. $\dfrac{3}{4}$
  4. $\dfrac{1}{2}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total outcomes = 36. Outcomes with sum < 7: (1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1) = 15 outcomes. Outcomes with sum >= 7 = 36 - 15 = 21. Probability = 21/36 = 7/12.

AI explanation

Using the fundamental principle of counting, there are 36 possible outcomes when two dice are thrown. The outcomes with a sum of at least 7 are 21 in total (6 for sum 7, 5 for sum 8, 4 for sum 9, 3 for sum 10, 2 for sum 11, and 1 for sum 12). The probability is 21 divided by 36, which simplifies to 7/12.

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