If $k> 0$ and the product of roots of the equations $x^{2}-3kx+2e^{\log k}-1=0$ is $7$ , then find the sum of the roots-

The product of the roots for x^2 - 3kx + 2e^(log k) - 1 = 0 is given by the constant term, which simplifies to 2k - 1. Setting this equal to 7 gives 2k - 1 = 7, meaning k = 4. The sum of the roots is given by the formula -(-3k)/1, which equals 3k. Substituting k = 4 makes the sum of the roots 12.

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