Multiple choice

A bus is moving with a speed of $50km/h$, can be stopped by brakes after atleast $6m$. If the same car is moving at a speed of $100km/h$. the minimum distance covered is

  1. $12m$
  2. $18m$
  3. $24m$
  4. $6m$
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C Correct answer
Explanation

Stopping distance is proportional to the square of speed. Doubling the speed from 50 km/h to 100 km/h multiplies the stopping distance by 4, so the distance becomes 6 × 4 = 24 m.

AI explanation

Using the equation of motion v^2 = u^2 + 2as, the stopping distance is proportional to the square of the initial velocity when the deceleration remains constant. The ratio of the squares of the initial speeds is 100 squared divided by 50 squared, which equals 4. Multiplying this factor of 4 by the initial stopping distance of 6 m yields a minimum stopping distance of 24 m.

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