A pair of dice is thrown. The probability of getting a total of $8$ or $10$ is.......
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A pair of dice is thrown. The probability of getting a total of $8$ or $10$ is.......
Total outcomes = 36. Sum of 8: (2,6), (3,5), (4,4), (5,3), (6,2) = 5 outcomes. Sum of 10: (4,6), (5,5), (6,4) = 3 outcomes. Total favorable = 8. Probability = 8/36 = 2/9.
When a pair of dice is thrown, the total possible outcomes are 36. To get a sum of 8, the favorable outcomes are (2, 6), (3, 5), (4, 4), (5, 3), and (6, 2), totaling 5 ways; to get a sum of 10, the favorable outcomes are (4, 6), (5, 5), and (6, 4), totaling 3 ways. The total number of favorable outcomes is 5 + 3 = 8. Using the classical probability formula, the probability is 8/36, which simplifies to 2/9.