Multiple choice

A solid cylinder of mass $20kg$ has length $1 m$ and radius $0.2$ $m$. Then its moment of inertia(in $kg-{ m }^{ 2 }$) about its geometrical axis is

  1. $0.8$ $kg-{ m }^{ 2 }$
  2. $0.4$ $kg-{ m }^{ 2 }$
  3. $0.2$ $kg-{ m }^{ 2 }$
  4. $20.0$ $kg-{ m }^{ 2 }$
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B Correct answer
Explanation

Moment of inertia of a solid cylinder about its axis = (1/2)MR^2. M = 20, R = 0.2. I = 0.5 * 20 * (0.2)^2 = 10 * 0.04 = 0.4.

AI explanation

The moment of inertia of a solid cylinder about its geometrical axis is given by the formula I = (1/2) * m * r^2. Substituting the given mass of 20 kg and the radius of 0.2 m, we get I = 0.5 * 20 * (0.2)^2. This simplifies to 10 * 0.04, resulting in 0.4 kg-m^2.

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