Multiple choice

A car, starting from rest, accelerates at the rate $\alpha$ through a distance $d$, then continues at a constant speed for time $t$ and then decelerates at the rate of $\alpha/ 2$to come to rest. If the total distance traveled is $15 d$ then :

  1. $d = \dfrac{1}{2} \alpha t^2$
  2. $d = \dfrac{1}{4} \alpha t^2$
  3. $d = \dfrac{1}{72} \alpha t^2$
  4. $d = \dfrac{1}{6} \alpha t^2$
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D Correct answer

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