Multiple choice

Two cars $A$ and $B$ are moving with same speed of 45$\mathrm { km } / \mathrm { hr }$ along same direction. If a third car C coming from opposite direction with a speed of 36$\mathrm { km }$ hr meets two cars in an interval of 5 minutes, the distance of separation of two cars $A$ and B should be $( i n k m )$

  1. 6.75

  2. 7.25

  3. 5.55

  4. 8.35
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A Correct answer
Explanation

Relative speed of C with respect to A and B = 45 + 36 = 81 km/hr. Time interval = 5 min = 5/60 hr = 1/12 hr. Distance = speed * time = 81 * (1/12) = 6.75 km.

AI explanation

Car C approaches cars A and B moving in the opposite direction, so their relative speed is the sum of their individual speeds, giving 45 + 36 = 81 km/hr. Converting this relative speed to meters per minute gives 81000 meters divided by 60 minutes, which equals 1350 meters per minute. The separation distance is the relative speed multiplied by the time interval of 5 minutes, resulting in 1350 multiplied by 5 to equal 6750 meters. Converting this distance into kilometers yields 6.75 km.

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