A die is tossed twice. What is the probability of getting a sum of $10$?
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A die is tossed twice. What is the probability of getting a sum of $10$?
A die tossed twice has 36 outcomes. Sum of 10 can be achieved by (4,6), (5,5), (6,4). There are 3 favorable outcomes. Probability = 3/36 = 1/12.
When a die is tossed twice, the total number of outcomes in the sample space is 6 * 6 = 36. The favorable outcomes for getting a sum of 10 are (4,6), (5,5), and (6,4), which gives 3 favorable combinations. Using the classical probability formula, the probability is 3/36, which simplifies to 1/12.