Multiple choice

If a dice is thrown twice, the probability of occurrence of $4$ atleast once, is

  1. $\cfrac { 11 }{ 36 } $
  2. $\cfrac { 7 }{ 12 } $
  3. $\cfrac { 35 }{ 36 } $

  4. None of these
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A Correct answer
Explanation

The probability of not getting a 4 in one throw is 5/6. For two throws, the probability of never getting a 4 is (5/6) * (5/6) = 25/36. Thus, the probability of getting at least one 4 is 1 - 25/36 = 11/36.

AI explanation

Using the complementary probability method, the total number of outcomes when a dice is thrown twice is 6 * 6 = 36. The probability of not getting a 4 on either throw is (5/6) * (5/6) = 25/36. Therefore, the probability of getting a 4 at least once is 1 - 25/36 = 11/36.

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