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Multiple choice

If both roots of the equation $a{ x }^{ 2 }+2xa+1+{ a }^{ 2 }-16=0$ are opposite in sign, then the range of $a$ is

  1. $\left( -\infty ,-4 \right) \cup \left( 4,\infty \right) $
  2. $\left( -4,4 \right) $
  3. $\left( -\infty ,-4 \right) \cup \left( 0,4 \right) $
  4. $\left( 0,4 \right) $
Reveal answer Fill a bubble to check yourself
C Correct answer

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