A body has speed $V, 2V$ and $3V$ in first $\dfrac{1}{3}$ of distance $S$, seconds $\dfrac{1}{3}$ of $S$ and third $\dfrac{1}{3}$ of $S$ respectively. Its average speed will be:

Using the average speed formula for three equal distances, 3abc divided by (ab + bc + ca), we substitute V, 2V, and 3V for the speeds. This calculation gives 3(V)(2V)(3V) over (2V^2 + 6V^2 + 3V^2), which simplifies to 18V^3 over 11V^2. The resulting average speed is 18/11 V.

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