Nature of the roots of the quadratic equation $2x^{2}-2\sqrt{6}x+3=0$ is:

To determine the nature of the roots for 2x squared minus 2 times the square root of 6x plus 3 equals 0, we calculate the discriminant using the formula b squared minus 4ac. Here, b squared is the square of negative 2 times the square root of 6, which is 24, and 4ac is 4 times 2 times 3, which is also 24. Since the discriminant is 24 minus 24, equaling 0, the roots are real, rational, and equal.

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