Multiple choice

A tourist being chased by an energy bear is running in a straight line towards his car at a speed of $4.0 \ m/s$. The car is a distance $d$ away. The bear is $26 \ m$ behind the tourist and running at $6.0 \ m/s$. The tourist reaches the car safely the maximum possible value for $d$ is:-

  1. $25 \ m$
  2. $26 \ m$
  3. $52 \ m$
  4. $50 \ m$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Tourist speed = 4 m/s, Bear speed = 6 m/s. Relative speed = 2 m/s. The bear covers the 26m gap in 26/2 = 13 seconds. In 13 seconds, the tourist covers 4 * 13 = 52 meters. Thus, the car must be at most 52 meters away.

AI explanation

The bear gains on the tourist at a relative speed of 6.0 m/s minus 4.0 m/s, which is 2.0 m/s. To cover the 26 m gap between them, the bear requires 26 divided by 2, or 13 seconds. In that same 13 seconds, the tourist runs a maximum distance of 4.0 m/s multiplied by 13 s, resulting in 52 m to reach the car safely.

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