Multiple choice

A dice is thrown once. The probability of getting the square of the number appearing on the dice to be a multiple of 9 is

  1. $\dfrac { 1 }{ 3 } $
  2. $\dfrac { 2 }{ 3 } $
  3. $\dfrac { 1 }{ 2 } $
  4. $\dfrac { 1 }{ 6 } $
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A Correct answer
Explanation

Possible outcomes: 1, 2, 3, 4, 5, 6. Squares: 1, 4, 9, 16, 25, 36. Multiples of 9: 9, 36. These correspond to numbers 3 and 6 on the dice. Probability = 2/6 = 1/3.

AI explanation

When a single die is thrown, the sample space of possible outcomes is the numbers 1, 2, 3, 4, 5, and 6. We find the squares of these outcomes to be 1, 4, 9, 16, 25, and 36, where only 9 and 36 are multiples of 9. Since 2 outcomes out of the 6 possibilities satisfy the condition, the probability is 2 divided by 6, which simplifies to 1/3.

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