Multiple choice

Two coins are tossed $1000$ times and the outcomes are recorded as below: No of heads $2$ $1$ $0$ Frequency $200$ $550$ $250$ Based on this information, the probability for at most one head is $\dfrac{a}{b}$. Where $(a,b)=1$, then

  1. $\dfrac{1}{5}$
  2. $\dfrac{1}{4}$
  3. $\dfrac{4}{5}$
  4. $\dfrac{3}{4}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total tosses = 1000. At most one head means 0 or 1 head. Frequency of 0 heads = 250, frequency of 1 head = 550. Total favorable = 250 + 550 = 800. Probability = 800 / 1000 = 4/5.

AI explanation

The probability of an event is calculated using empirical probability by dividing the frequency of the favourable outcomes by the total frequency. The event of getting at most one head corresponds to getting exactly one head or no heads, so we add their frequencies to get 550 + 250 = 800 favourable outcomes. Dividing by the total frequency of 1000 gives the probability as 800/1000, which simplifies to 4/5.

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