Solve the following pairs of equations. $3x-y=0$; $x-2=0$
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Solve the following pairs of equations. $3x-y=0$; $x-2=0$
None of these
From the second equation, x=2. Substituting into the first equation: 3(2) - y = 0, so y=6.
The second equation directly states that x - 2 = 0, which means x = 2. Substituting this value into the first equation, 3x - y = 0, results in 3(2) - y = 0. Solving for y gives y = 6, so the solution to the system of equations is x = 2 and y = 6.