A coin is tossed $5$ times. The probability of $2$ heads and $3$ tails is:
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A coin is tossed $5$ times. The probability of $2$ heads and $3$ tails is:
Total outcomes = 2^5 = 32. Favorable outcomes (2 heads) = 5C2 = 10. Probability = 10/32 = 5/16.
The question asks for the probability of getting exactly 2 heads and 3 tails in any order, which has 5 choose 2, or 10, favourable arrangements. The total number of outcomes for tossing a coin 5 times is 2 raised to the power of 5, which is 32. Using the classical probability formula, the calculation is 10 divided by 32. The result is 5/16.