Multiple choice

If one of the zeroes of the quadratic polynomial $kx^2 + k x -16 $ is $3$, then the value of $k$ is

  1. $\dfrac{4}{3}$
  2. $-\dfrac{4}{3}$
  3. $\dfrac{2}{3}$
  4. $-\dfrac{2}{3}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

If 3 is a zero, then k(3)^2 + k(3) - 16 = 0. 9k + 3k - 16 = 0. 12k = 16. k = 16/12 = 4/3.

AI explanation

Since 3 is a zero of the polynomial kx^2 + kx - 16, substitute x = 3 into the expression and set it equal to zero. This gives the equation 9k + 3k - 16 = 0. Combining like terms yields 12k = 16, so k = 16/12, which simplifies to 4/3. The value of k is 4/3.

Keep practicing — related questions