Solve the following pair of equations: $13+2y= 9x$, $3y= 7x$
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Solve the following pair of equations: $13+2y= 9x$, $3y= 7x$
Substitute 3y = 7x into the first equation. From 3y = 7x, y = 7x/3. Substitute into 13 + 2y = 9x: 13 + 2(7x/3) = 9x. Multiply by 3: 39 + 14x = 27x. 39 = 13x, so x = 3. Then y = 7(3)/3 = 7.
From the second equation, substitute y = 7x/3 into the first equation to get 13 + 2(7x/3) = 9x. Multiplying by 3 yields 39 + 14x = 27x, which simplifies to 13x = 39, giving x = 3. Plugging this back gives y = 7(3)/3 = 7. The solution is x = 3, y = 7.