Multiple choice

A man divided two sums of money among 4 sons R, S, T, U the first in the ratio 4 : 3 : 2 : 1 and the second in the ration 5 : 6 : 7 : 8 If the second sum of money is twice the first the first sum which son receives the largest part?

  1. R

  2. S

  3. T

  4. U

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A Correct answer
Explanation

The first sum is divided in ratio 4:3:2:1 (total 10 parts). The second sum is divided in ratio 5:6:7:8 (total 26 parts). Let the first sum be S1 and the second be S2 = 2*S1. R's share is 0.4*S1 + (5/26)*2*S1 = 0.4*S1 + 0.384*S1 = 0.784*S1. Comparing shares, R receives the largest portion.