Multiple choice

A person draws out two balls successively from a bag containing $6$ red and $4$ white balls. The probability that atleast one of them will be red, is

  1. $\dfrac {78}{90}$
  2. $\dfrac {30}{90}$
  3. $\dfrac {48}{90}$
  4. $\dfrac {12}{90}$
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A Correct answer
Explanation

Total balls = 10. Probability of no red (all white) = (4/10) * (3/9) = 12/90. Probability of at least one red = 1 - 12/90 = 78/90.

AI explanation

Using the complement rule, the probability of drawing at least one red ball is equal to 1 minus the probability of drawing no red balls. The probability of drawing two white balls successively from the bag of 6 red and 4 white balls is (4/10) * (3/9), which equals 12/90. Subtracting this from 1 gives 1 - 12/90, which equals 78/90. The result is 78/90.

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