The roots of the equation $ix^{2}-4x-4=0$ are
Reveal answer
Fill a bubble to check yourself
The roots of the equation $ix^{2}-4x-4=0$ are
none of these
We solve the given quadratic equation using the quadratic formula, x = (-b +/- sqrt(b^2 - 4ac)) / 2a. Substituting a = i, b = -4, and c = -4 gives the discriminant as (-4)^2 - 4(i)(-4) = 16 + 16i = 16(1 + i). Using the square root of 1 + i, the roots are calculated as x = 2 +/- sqrt(1 + i), which are complex numbers that do not match any specific pair of imaginary numbers listed. Therefore, the correct choice is none of these.