The roots of the equation (x-2)(x-3)(x+3) are _______.
Reveal answer
Fill a bubble to check yourself
The roots of the equation (x-2)(x-3)(x+3) are _______.
(2,3,-3)
(3,2,-4)
(1,2,3)
(2,2,-3)
The roots of (x-2)(x-3)(x+3) = 0 are found by setting each factor to zero: x-2=0, x-3=0, x+3=0. Thus, x=2, x=3, x=-3.
To find the roots of the equation (x - 2)(x - 3)(x + 3) = 0, we set each individual factor equal to zero. Solving x - 2 = 0 gives x = 2. Solving x - 3 = 0 gives x = 3, and solving x + 3 = 0 gives x = -3. Therefore, the roots of the equation are 2, 3, and -3.