$X$ is three times as old as $Y, Z$ was twice as old as $x$ four years ago. In the four year time, $x$ will be of $31$ years. What is the present age of $y$ and $z$.

Let the present ages of X, Y, and Z be x, y, and z. In four years, X will be 31 years old, so x plus 4 equals 31, meaning x is 27. X is three times as old as Y, so y equals 27 divided by 3, which is 9. Four years ago, Z was twice as old as X, giving the equation z minus 4 equals 2 times (27 minus 4), so z minus 4 equals 46 and z equals 50. The present ages of Y and Z are 9 years and 50 years.

• Thanks
• Wrong explanation