Multiple choice

Two dice were thrown simultaneously. Then find the probability of g etting the sum of outcomes less than 7

  1. $\dfrac{7}{12}$
  2. $\dfrac{5}{12}$
  3. $\dfrac{5}{18}$
  4. $\dfrac{1}{9}$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total outcomes for two dice is 36. Sums less than 7 are: (1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1). There are 15 such outcomes. Probability = 15/36 = 5/12.

AI explanation

There are 36 possible outcomes when two dice are thrown simultaneously. The favorable outcomes for getting a sum less than 7 are 15, consisting of 5 outcomes for a sum of 6, 4 outcomes for a sum of 5, 3 outcomes for a sum of 4, 2 outcomes for a sum of 3 and 1 outcome for a sum of 2. The probability is the number of favorable outcomes divided by the total outcomes, calculated as 15/36. Simplifying this fraction by dividing the numerator and denominator by 3 gives the result 5/12.

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