Multiple choice 2K coins (K is an integer) each with probability P(O $\dfrac{K}{2K+1}$ $\dfrac{K+1}{2K}$ $\dfrac{K+1}{2K+1}$ $\dfrac{2K}{K+1}$ Reveal answer Fill a bubble to check yourself C Correct answer Explanation For 2K tosses, equate the probabilities of K heads and K+1 heads. Cancelling the common binomial factor gives (1-P)/P = (K+1)/K. Solving yields P = (K+1)/(2K+1).