Two persons A and B toss a coin 50 times each together. Find the probability both of them get tails at the same time.
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Two persons A and B toss a coin 50 times each together. Find the probability both of them get tails at the same time.
Each toss is independent. Probability of tails for one person is 1/2. Probability both get tails in one toss is 1/2 * 1/2 = 1/4. For 50 tosses, it is (1/4)^50.
For each of the 50 rounds, both A and B must get tails for them to get tails at the same time. The probability of A getting a tail is 1/2, and the probability of B getting a tail is 1/2. Because their coin tosses are independent events, the probability that both get a tail in a single round is 1/2 times 1/2, which is 1/4. For this to happen in all 50 rounds, we raise this probability to the power of 50, giving (1/4)^50.