Nine cards are labelled $0, 1, 2, 3, 4, 5, 6, 7, 8$. Two cards are drawn at random and put on a table in a successive order, and then the resulting number is read, say, $07$(seven), $14$(fourteen) and so on. The probability that the number is even, is?

A number formed by two digits is even if and only if its last digit is even. The available even digits from the set of nine cards are 0, 2, 4, 6, and 8, giving 5 favorable choices for the second position. The first position can be filled by any of the remaining 8 cards. The total number of possible 2-digit numbers is 9 * 8 = 72, and the number of favorable even numbers is 8 * 5 = 40. Using the classical definition of probability, the result is 40/72, which simplifies to 5/9. The result is 5/9.

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