Multiple choice

A bag contains $5$ red balls and $8 $ blue balls. It also contains $4$ green and $7$ black balls. If a ball is drawn at random, then find the probability that it is not green.

  1. $\dfrac{5}{6}$
  2. $\dfrac{1}{4}$
  3. $\dfrac{1}{6}$
  4. $\dfrac{7}{4}$
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A Correct answer
Explanation

Total balls = 5 + 8 + 4 + 7 = 24. Green balls = 4. Probability of green = 4/24 = 1/6. Probability of not green = 1 - 1/6 = 5/6.

AI explanation

The total number of balls in the bag is 5 + 8 + 4 + 7, which equals 24. The number of balls that are not green is 24 - 4 = 20. Using the basic probability formula, the probability of drawing a non-green ball is 20/24, which simplifies to 5/6. The result is 5/6.

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