The area of the square that can be inscribed in a circle of radius $8$ cm is :
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The area of the square that can be inscribed in a circle of radius $8$ cm is :
A square inscribed in a circle has a diagonal equal to the circle's diameter. Diameter = 2 * 8 = 16 cm. Let side be s. s^2 + s^2 = 16^2 = 256. 2s^2 = 256, s^2 = 128. The area of the square is s^2 = 128 cm^2.
For a square inscribed in a circle, the diagonal of the square equals the diameter of the circle, which is 2 times 8, or 16 cm. Using the relation between a square's side (s) and diagonal (d), d = s times the square root of 2, so the side is 16 divided by the square root of 2, which simplifies to 8 times the square root of 2 cm. The area is the side squared, yielding 128 square cm.