Multiple choice

'A' is 16 years elder than 'B'. But 'B's' $\dfrac {1}{2}$ age is equal to $\dfrac {1}{3}$ age of 'A', then what is the present age of 'A' and 'B'

  1. $A=32, B=16$
  2. $A=48, B=32$
  3. $A=40, B=42$
  4. $A=46, B=30$
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B Correct answer
Explanation

A = B + 16. Also (1/2)B = (1/3)A, so A = 1.5B. Equating: B + 16 = 1.5B, 0.5B = 16, B = 32. Then A = 32 + 16 = 48.

AI explanation

Let B's present age be x, making A's present age x + 16. The problem states that half of B's age equals a third of A's age, giving the equation x / 2 = (x + 16) / 3. Cross-multiplying yields 3x = 2x + 32, which means x = 32. Therefore, B is 32 years old and A is 32 + 16 = 48 years old.