Multiple choice

A coin and a die is tossed simultaneously. Find the probability of the event that 'tail' and a prime number turns up?

  1. $\displaystyle\frac{1}{2}$
  2. $\displaystyle\frac{1}{4}$
  3. $\displaystyle\frac{1}{3}$
  4. $\displaystyle\frac{2}{3}$
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B Correct answer
Explanation

Total outcomes = 2 (coin) * 6 (die) = 12. Favorable outcomes (Tail, Prime) are (T, 2), (T, 3), (T, 5). Probability = 3/12 = 1/4.

AI explanation

When a coin and a die are tossed, the sample space contains 12 outcomes. The event of getting a tail has 6 outcomes, and the prime numbers on a die are 2, 3, and 5. The combination of a tail and a prime number gives 3 favorable outcomes. Using the classical probability formula, 3/12 simplifies to 1/4. The result is 1/4.

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