Multiple choice

If the sum of the roots of the equation $(a + 1)x^{2} + (2a + 3)x + (3a + 4) = 0$, where $a \neq -1$, is $-1$, then the product of the roots is

  1. $4$
  2. $2$
  3. $1$
  4. $-2$
  5. $-4$
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B Correct answer
Explanation

Sum of roots = -b/a = -(2a+3)/(a+1) = -1. 2a+3 = a+1 -> a = -2. Product of roots = c/a = (3a+4)/(a+1). Substitute a = -2: (3(-2)+4)/(-2+1) = -2/-1 = 2.

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