If the roots of the equation $x^{2} + px + c = 0$ are $(2, -2)$ and the roots of the equation $x^{2} + bx + q = 0$ are $(-1, -2)$, then the roots of the equation $x^{2} + bx + c = 0$ are

For the first equation x^2 + px + c = 0 with roots 2 and -2, the constant c is the product of its roots, so c = (2)(-2) = -4. For the second equation x^2 + bx + q = 0 with roots -1 and -2, the coefficient b is the negative sum of its roots, so b = -(-1 - 2) = 3. The new equation is x^2 + 3x - 4 = 0, which factors as (x + 4)(x - 1) = 0, yielding roots of 1 and -4.

• Thanks
• Wrong explanation