Two unbiased dice are rolled once. Find the probability of getting sum less than $5$.
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Two unbiased dice are rolled once. Find the probability of getting sum less than $5$.
Total outcomes = 36. Sum < 5: (1,1), (1,2), (1,3), (2,1), (2,2), (3,1). Total favorable = 6. Probability = 6/36 = 1/6.
The total number of outcomes when two unbiased dice are rolled is 36. The combinations resulting in a sum less than 5 are (1,1), (1,2), (2,1), (1,3), (2,2), and (3,1), giving 6 favorable outcomes. Therefore, the probability is 6 divided by 36, which simplifies to 1/6.