Multiple choice

A coin is tossed $3$ times. The probability of getting head and tail alternately is

  1. $\displaystyle \frac{1}{8}$
  2. $\displaystyle \frac{1}{2}$
  3. $\displaystyle \frac{1}{4}$
  4. $\displaystyle \frac{1}{6}$
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C Correct answer
Explanation

Total outcomes for 3 tosses = 2^3 = 8. Outcomes: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. Favorable outcomes (alternating): HTH, THT. Probability = 2/8 = 1/4.

AI explanation

When a coin is tossed 3 times, the total number of sample points in the sample space is 2^3, which equals 8. The favorable outcomes for getting heads and tails alternately are HTH and THT. Since there are 2 favorable outcomes, the probability is 2 divided by 8, which equals 1/4.

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