A piece of wire 20 cm long is bent into the form of an arc of a circle subtending an angle of $60^0$ at its centre. The radius of the circle is

The length of the wire becomes the arc length, so $L = 20$ cm. Using the arc length formula $L = r \theta$ where the angle $\theta = 60^\circ = \pi/3$ radians, we substitute the values to get $20 = r(\pi/3)$. Solving for the radius yields $r = 60/\pi$ cm.

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