Multiple choice If the roots of the given equation $(\cos p - 1)x^2+(\cos p)x+\sin p=0$ are real, then $p \in (-\pi, 0)$ $p \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$ $p \in (0, \pi)$ $p \in (0, 2\pi)$ Reveal answer Fill a bubble to check yourself C Correct answer