In a box, there are $8$ alphabets cards with the letters: $S, S, A, A, A, H, H, H$. Find the probability that the word $ASH$ will form if three cards are drawn simultaneously.

The total number of ways to draw 3 cards simultaneously from 8 is 8C3, which equals 56. To form the word ASH, we must draw one A from 3, one S from 2, and one H from 3, giving 3C1 times 2C1 times 3C1, which equals 18. Dividing the favorable outcomes by the total outcomes gives 18/56, which simplifies to 9/28. The result is 9/28.

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