Multiple choice

The distance of a chord of length 16 cm from the centre of a circle of radius 10 cm is

  1. 5

  2. 6

  3. 7

  4. 8s
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The perpendicular from the center to a chord bisects the chord, giving a right triangle with hypotenuse 10 cm and one leg 8 cm. The distance is sqrt(10^2 - 8^2) = sqrt(36) = 6 cm, so option B is correct.

AI explanation

A line from the center perpendicular to the chord bisects the chord, creating a right triangle with a hypotenuse equal to the radius of 10 cm and one leg equal to half the chord length, 8 cm. Using the Pythagorean theorem, the distance from the center is sqrt(10^2 - 8^2) = sqrt(100 - 64) = sqrt(36). The distance is 6 cm.

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