Multiple choice

A father is twice as old as his son. $20$ years back, he was twelve times as old as his son. What are their present ages ?

  1. $24$ years, $12$ years
  2. $44$ years, $22$ years
  3. $48$ years, $44$ years

  4. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let son's age be x, father's be 2x. 20 years ago: (2x - 20) = 12(x - 20). 2x - 20 = 12x - 240. 10x = 220, so x = 22. Father is 44. Option B matches.

AI explanation

Let the present age of the son be x years, which makes the father's present age 2x years. Twenty years back, their ages were (x - 20) and (2x - 20), so we can write the equation 2x - 20 = 12(x - 20). Solving this equation gives 2x - 20 = 12x - 240, meaning 10x = 220 and x = 22. Therefore, the son is 22 years old and the father is 44 years old.

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