Multiple choice

The present age of a father is $3$ years more than $3$ times the age of his son. Three years after, father's age will be $10$ years more than twice the age of the son. The father's present age is

  1. $33$ years
  2. $39$ years
  3. $45$ years
  4. $40$ years
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A Correct answer
Explanation

Let S be the son's age and F be the father's age. F = 3S + 3. Three years later, F + 3 = 2(S + 3) + 10. Substituting the first into the second: 3S + 3 + 3 = 2S + 6 + 10, which simplifies to 3S + 6 = 2S + 16, so S = 10. Then F = 3(10) + 3 = 33.

AI explanation

Let the son's present age be x. The father's present age is 3x + 3, and three years later their ages will be x + 3 and 3x + 6. The equation is 3x + 6 = 2(x + 3) + 10, which simplifies to 3x + 6 = 2x + 16, giving x = 10. The father's present age is 3 times 10 plus 3, or 33 years.

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